A and B run a race of 960 m. If A gives a start of 96 m to B, he defeats him by 12 sec and if A gives a start of 288 m to B, he loses by 4 sec. What is the speed of B in m/sec?
Answer & explanation
Correct answer: option 1
Let the speed of B = x m/s
ATQ, (time taken by A in both case)
⇒ \(\frac{960 - 96}{x}\) - 12 = \(\frac{960 - 288}{x}\) + 4
⇒ \(\frac{864}{x}\) - \(\frac{672}{x}\) = 16
⇒ \(\frac{192}{x}\) = 16
⇒ x = \(\frac{192}{16}\)
⇒ x = 12 m/sec.