Match List – I with List – II.

Choose the correct answer from the options given below:

A - IV, B - I, C - II, D - III

The correct answer is Option (3) → A - IV, B - I, C - II, D - III

$\text{(A)}\; x_1+x_2=2,\; P=\frac{1}{2}$

$E(X)=\frac{x_1+x_2}{2}=1 \Rightarrow \text{(IV)}$

$\text{(B)}\; B(4,\frac{1}{3})$

$\text{Mean}=np=4\cdot\frac{1}{3}=\frac{4}{3} \Rightarrow \text{(I)}$

$\text{(C)}\; \text{Variance of Binomial } (n=3,p=\frac{1}{6})$

$npq=3\cdot\frac{1}{6}\cdot\frac{5}{6}=\frac{15}{36}=\frac{5}{12} \Rightarrow \text{(II)}$

$\text{(D)}\; \text{Mean}=np=3\cdot\frac{1}{6}=\frac{1}{2} \Rightarrow \text{(III)}$

A–IV,\; B–I,\; C–II,\; D–III