The equation of normal to the curve \(y=\cos x\) at origin is

\(x+y=0\) \(y=0\) \(x=1\) \(x=0\)

\(x=0\)

To find normal we have to find slope of that normal at $(0,1).$ $y\text{'}\; =\; -sinx$ $slope\; of\; the\; normal\; is\; \$m\_\{slope\}\; =\; \backslash frac\{1\}\{-\; sinx\}|\_\{x=0\}\; =\; \backslash infty\$$ $Equation\; of\; normal\; is\; \$y\; -\; 0\; =\; m\_\{normal\}\; (x-0)\; \$$ $Since\; \$\; m\_\{normal\}\; =\; \backslash infty\$$ $Equation\; of\; normal\; is\; x\; =\; 0.$