Three resistors of value 2r, 3r and 5r are connected in series with each other. The voltage source applied to this combination is 20 V. If the lowest resistance is 4 Ohms, what is value of current flowing through the circuit?
Answer & explanation
Correct answer: option 2
Reff = 2r + 3r + 5r = 10r
lowest resistance = 2r = 4 Ohms
Thus, r = 2 Ohms
Reff = 10r = 10 (2 Ohms) = 20 Ohms
I = V/Reff = 20 V/20 Ohms = 1 A