If cot55θ + tan97θ = 2, find 2sinθ + cosθ .
Answer & explanation
Correct answer: option 4
If cotnθ + tannθ = 2 then cotθ = tanθ = 1 where θ = 45°
Now,
⇒ 2sinθ + cosθ = 2 × (\(\frac{1}{√2}\)) + (\(\frac{1}{√2}\))
= 2 × \(\frac{1}{√2}\) + \(\frac{1}{√2}\) = \(\frac{3}{√2}\)