If cot55θ + tan97θ = 2, find 2sinθ + cosθ .

1  \(\frac{3}{√3}\)   \(\frac{5}{√2}\)   \(\frac{3}{√2}\)

\(\frac{3}{√2}\)

If cotnθ + tannθ = 2 then cotθ = tanθ = 1 where θ = 45° Now, ⇒ 2sinθ + cosθ = 2 × (\(\frac{1}{√2}\)) + (\(\frac{1}{√2}\))  = 2 × \(\frac{1}{√2}\) + \(\frac{1}{√2}\) =  \(\frac{3}{√2}\)