The maximum value of 3sin2Q + 4cos2

CUET Preparation Today

Start Free Mocks

Home Questions PURR9T46SA

Target Exam

CUET

Subject

General Aptitude Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

The maximum value of 3sin²Q + 4cos²Qis?

Options:

Correct Answer:

Explanation:

⇒ 3sin²Q+ 4cos²Q

= 3sin² Q + 4(1-sin²Q) [ sin²Q + cos²Q = 1]

= 4 - sin²Q

⇒ The maximum value of eqn is when sin²Q is minimum i.e.

When Q = 0, ⇒ sin²0° = 0

⇒ Therefore, 4 is the maximum value.