In a step-down transformer, 22 kV is converted into 220 V. The number of turns in the primary coil is 60000. The number of turns in the secondary coil will be

600

The correct answer is Option (3) → 600

For a transformer: $\frac{V_s}{V_p} = \frac{N_s}{N_p}$

Given: $V_p = 22\ \text{kV} = 22000\ \text{V}$, $V_s = 220\ \text{V}$, $N_p = 60000$

$N_s = N_p \frac{V_s}{V_p} = 60000 \cdot \frac{220}{22000} = 60000 \cdot 0.01 = 600$

Number of turns in the secondary coil = 600