Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

In any Bohr orbit of the hydrogen atom, the ratio of kinetic energy to potential energy of the electron is

Options:

1/2

2

-1/2

-2

Correct Answer:

-1/2

Explanation:

K.E = $\frac{k Z e^2}{2 r}$ and P.E. = $-\frac{k Z e^2}{r}$ ;  ∴  $\frac{K . E .}{P . E .}=-\frac{1}{2}$