The lengths of the diagonals of a rhombus are 16 cm and 30 cm, respectively. What is the perimeter of the rhombus?
Answer & explanation
Correct answer: option 1
AO can be written as (\(\frac{AD}{2}\))= \(\frac{16}{2}\)= 8 cm
And, DO can be written as (\(\frac{BD}{2}\))
= \(\frac{30}{2}\) = 15 cm
Then, consider the triangle AOD and apply Pythagoras theorem,
AD2 = AO2 + DO2
AD2 = 82 + 152
AD2 = 64 + 225 = 289
AD = 17 cm
The perimeter of rhombus = 4 × side of the rhombus
= 4 × 17 = 68 cm