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If $x^4 - 12x^2 + 1 = 0 $, then what will be the value of $x^4 + \frac{1}{x^4}$ |
142 146 10 144 |
142 |
We know that, If $K+\frac{1}{K}=n$ then, $K^2+\frac{1}{K^2}$ = n2 – 2 If $x^4 - 12x^2 + 1 = 0 $, Divide by x2 on the both sides of equation we get, x2 + \(\frac{1}{x^2}\) = 12 then the value of $x^4 + \frac{1}{x^4}$ = 122 – 2 = 142 |
