If a matrix has 28 elements, what are the possible orders it can have?

5 6 7 8

6

We know that, if a matrix is of order mxn, then it has mn elements, where m and n are natural numbers. We have, $m × n = 28$ $⇒(m, n) = \{(1, 28), (2, 14), (4, 7), (7, 4), (14, 2), (28, 1)\}$ So, the number of possible orders it can have $1 × 28, 2×14,4×7, 7×4, 14×2,28×1$.