The function f: R→R, f(x) =x^2 is :

The correct answer is Option (4) → neither injective nor surjective

$f(x) =x^2$ so $f^{-1}(x)=\sqrt{x}$

for $x<0$

$f^{-1}(x)$ don't exist ⇒ Not Surjective

$f(-x)=f(x)$ ⇒ Not Injective