Practicing Success
Practicing Success
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The function $f: R→R, f(x) =x^2 $ is : |
injective but not surjective surjective but not injective injective as well as surjective neither injective nor surjective |
neither injective nor surjective |
The correct answer is Option (4) → neither injective nor surjective $f(x) =x^2$ so $f^{-1}(x)=\sqrt{x}$ for $x<0$ $f^{-1}(x)$ don't exist ⇒ Not Surjective $f(-x)=f(x)$ ⇒ Not Injective |
