Practicing Success
Practicing Success
CUET Preparation Today
The three capacitors in figure, store a total energy in µJ of
|
12 36 48 80 |
48 |
Total capacitance = 6 µF Applied voltage = 4v Stored energy U = $\frac{1}{2} C V^2=\frac{1}{2} \times 6 \times 10^{-6} \times(4)^2$ = 48µF |
