A carbon resistor has colour bands Yellow, Orange, Blue and Silver as…

The correct answer is Option (3) → \( (43\times10^{6}\pm10\%)\,\Omega \)

In the colour code of a carbon resistor the first two bands give the first two digits, the third band gives the power of ten (multiplier), and the last band gives the tolerance.

    Yellow = 4, Orange = 3 (digits) → 43
    Blue = 6 (multiplier) → \( 10^{6} \)
    Silver = \( \pm10\% \) (tolerance)

    \( R = (43\times10^{6}\pm10\%)\,\Omega \)

Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), and it also appears to be out of the CUET 2026 syllabus.

NCERT (Pre-rationalised edition, 2022-23):
Resistivity of Various Materials – “… The resistors have a set of co-axial coloured rings on them whose significance are listed in Table 3.2. The first two bands from the end indicate the first two significant figures of the resistance in ohms. The third band indicates the decimal multiplier (as listed in Table 3.2). The last band stands for tolerance or possible variation in percentage about the indicated values.”