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If x2 - 3x + 1= 0 and x > 1, then the value of x2 + \(\frac{1}{x^2}\)will be: |
3 9 7 4 |
7 |
If x2 - 3x + 1= 0 Divide by x on both sides, x + \(\frac{1}{x}\) = 3 x2 + \(\frac{1}{x^2}\) = 32 - 2 = 7
If x + \(\frac{1}{x}\) = a then, x2 + \(\frac{1}{x^2}\) = a2 - 2 |
