The charge flowing in an electrical circuit is given by the equation $Q=t^2-2t+4$. The current in the circuit at $t = 2$ sec is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 2 A
Current (I) due to flow of charge is -
$I=\frac{dQ}{dt}$
where,
$\frac{dQ}{dt}$ = Charge flowing per time
$∴I=\frac{d(t^2-2t+4)}{dt}$
$=[2t-2]_{t=2}$
$=2A$