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The charge flowing in an electrical circuit is given by the equation $Q=t^2-2t+4$. The current in the circuit at $t = 2$ sec is: |
2 A 0 A 4 A 3 A |
2 A |
The correct answer is Option (1) → 2 A Current (I) due to flow of charge is - $I=\frac{dQ}{dt}$ where, $\frac{dQ}{dt}$ = Charge flowing per time $∴I=\frac{d(t^2-2t+4)}{dt}$ $=[2t-2]_{t=2}$ $=2A$ |
