Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The shortest wavelength in the Lyman series of hydrogen spectrum is 912 Å corresponding to a photon energy of 13.6 eV. The shortest wavelength in the Balmer series is about

Options:

3648 Å

8208 Å

1228 Å

6566 Å

Correct Answer:

3648 Å

Explanation:

In Lyman series $\left(\lambda_{\min }\right)_L=\frac{1}{R}$ and $\left(\lambda_{\min }\right)_B=\frac{4}{R}$

$\Rightarrow\left(\lambda_{\min }\right)_B=4 \times\left(\lambda_{\min }\right)_L=4 \times 912$ = 3648 Å