Practicing Success
Function $f (x) = \sin x + \tan x + sgn (x^2-6x+10)$ is |
periodic with period 2π periodic with period π non-periodic none of these |
periodic with period 2π |
$sgn (x^2-6x+10)=1=sgn(x^2-2×3x+9+1)$ $⇒sgn((x-3)^2+1)=1$ as $(x-3)^2≥0$ $(x-3)^2+1>0$ so $f(x)=\sin x + \tan x + 1$ as period of $\sin x$ is 2π period of $\tan x$ is 2π Period is 2π |