Area of the region bounded by the curve \(y^2=4x, y-\) axis and the line \(y=3\) is1\(2\)2\(\frac{9}{4}\)3\(\frac{9}{3}\)4\(\frac{9}{2}\)Answer & explanation+Correct answer: option 2Required area =\(\left|\int_{0}^{2}\frac{y^2}{4}dy\right|\)
