Area of the region bounded by the curve \(y^2=4x, y-\) axis and the line \(y=3\) is

\(2\) \(\frac{9}{4}\) \(\frac{9}{3}\) \(\frac{9}{2}\)

\(\frac{9}{4}\)

Required area =\(\left|\int_{0}^{2}\frac{y^2}{4}dy\right|\)