The interval on which \(f(x)=2x^3+9x^2+12x-1\) is decreasing is
Answer & explanation
Correct answer: option 3
\(f^{'}(x)=6x^2+18x+12=3(x^2+3x+2) = 3(x^2 + 2x+x+2) = 3(x+2)(x+1)<0\)
$\Rightarrow -2<x<-1 $
The interval on which \(f(x)=2x^3+9x^2+12x-1\) is decreasing is
Correct answer: option 3
\(f^{'}(x)=6x^2+18x+12=3(x^2+3x+2) = 3(x^2 + 2x+x+2) = 3(x+2)(x+1)<0\)
$\Rightarrow -2<x<-1 $