CUET Preparation Today
If Laspeyre's index number =160, Paasche's index number =90. then Fisher's ideal index number is : |
30 120 140 160 |
120 |
The correct answer is Option (2) → 120 Laspeyre's index, L = 160 Paasche's index, P = 90 Fisher's index = $\sqrt{L×P}$ $=\sqrt{160×90}$ $=\sqrt{14400}=120$ |
