$\int\limits_{-1}^{1} \frac{|x-2|}{x-2}

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Definite Integration

Question:

$\int\limits_{-1}^{1} \frac{|x-2|}{x-2} dx, x \neq 2$ is equal to:

Options:

-1

-2

Correct Answer:

-2

Explanation:

The correct answer is Option (4) → - $2 \sin x + x + C$

$\int\limits_{-1}^{1} \frac{|x-2|}{x-2} dx = \int\limits_{-1}^{1} \frac{-(x-2)}{x-2} dx$

$= [-x]_{-1}^{1} = -2$