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-- Mathematics - Section B1
Indefinite Integration
The value of $∫e^x[f(x)+f'(x)]dx$ is :
$e^x+f(x)+C$
$e^x-f(x)+C$
$2e^x.f(x)+C$
$e^x.f(x)+C$
The correct answer is Option (4) → $e^x.f(x)+C$
we know that
$\frac{d}{dx}(e^xf(x))=e^x(f(x)+f'(x))$
$⇒\int e^x(f(x)+f'(x))dx=e^xf(x)$