Two points charges q1 = +1 µC and q2 = – 2 µC are placed at A and B respectively as shown in the figure. The distance between q1 and q2 is 4 cm.

A line of force emanates from q1 making an angle 90º with AB. This line of force

enters q2 at an angle 90° enters q2 at an angle 60° enters q2 at an angle 45° does not enter q2 but goes off to ∞

enters q2 at an angle 60°

$\frac{\sin \beta}{2}=\frac{\sin \alpha}{2} \sqrt{\frac{\left|q_1\right|}{\left|q_2\right|}}$