In a circles with center Q, ZXWQ is a parallelogram where X is a point on the minor arc ZW.  What is the measure of ∠ZQW?

260° 140° 240° 120°

120°

Let ∠ZXW = θ ⇒ Opposite angles in parallelogram are equal Therefore, ∠ZQW = ∠ZXW,  ⇒ y = θ Now, ∠ZQW = 2 ∠ZVW ⇒ y = 2 (180° - θ)   (θ = y) ⇒ θ = 360° - 2θ ⇒ 3 θ = 360° ⇒ θ = 120° ⇒ θ = y = 120°