Pipes A and B are emptying pipes and can empty a tank in 6 hours and 16 hours, respectively. C is a filling pipe. All the three pipes were opened together. They took 80 minutes to empty $\frac{5}{18}th$ of the tank. Pipe C alone can fill the tank in:
Answer & explanation
Correct answer: option 1
A- = 6 hours, B- = 16 hours,
⇒ Let the efficiency of C be x, then
⇒ (8 + 3 - X ) x \(\frac{80}{60}\) = 48 x \(\frac{5}{18}\)
⇒ (11 - X) x \(\frac{4}{3}\) = \(\frac{40}{3}\)
⇒ (11 - X) = 10,
⇒ X = 11 - 10,
⇒ X = 1,
⇒ Time taken by C to fill the tank alone = \(\frac{48}{1}\) = 48 hours.