Pipes A and B are emptying pipes and can empty a tank in 6 hours and 16 hours, respectively. C is a filling pipe. All the three pipes were opened together. They took 80 minutes to empty $\frac{5}{18}th$ of the tank. Pipe C alone can fill the tank in:

48 hours

A- = 6 hours, B- = 16 hours,

⇒ Let the efficiency of C be x, then

⇒ (8 + 3 - X ) x \(\frac{80}{60}\) = 48 x \(\frac{5}{18}\)

⇒ (11 - X) x \(\frac{4}{3}\) = \(\frac{40}{3}\)

⇒ (11 - X) = 10,

⇒ X = 11 - 10,

⇒ X = 1,

⇒ Time taken by C to fill the tank alone = \(\frac{48}{1}\) = 48 hours.