Differentiate the functions sin(log x), x > 0 with respect to x.

The correct answer is Option (3) → $\frac{\cos(\log x)}{x}$ ##

Let $y = \sin(\log x)$.

Using chain rule, we have

$\frac{dy}{dx} = \cos(\log x) \cdot \frac{d}{dx}(\log x) = \frac{\cos(\log x)}{x}$