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-- Mathematics - Section B2
Calculus
If $x^3+y^3=xy,$ then $\frac{dy}{dx}$ is equal to :
$\frac{y+3x^2}{3y^2+x}$
$\frac{y-3x^2}{3y^2-x}$
$\frac{y+3x^2}{3y^2-x}$
$\frac{2y-x^2}{y^2-3x}$