Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

If $x^3+y^3=xy,$ then $\frac{dy}{dx}$ is equal to :

Options:

$\frac{y+3x^2}{3y^2+x}$

$\frac{y-3x^2}{3y^2-x}$

$\frac{y+3x^2}{3y^2-x}$

$\frac{2y-x^2}{y^2-3x}$

Correct Answer:

$\frac{y-3x^2}{3y^2-x}$