How much an angular distance will be covered by the minute hand of a correct clock in a period of 1 h 45 min? |
850° 345° 270° 630° |
630° |
The correct answer is Option (4) → 630° The minute hand moves:
Given time = 1 hour 45 minutes = 105 minutes $\text{Angular distance} = 105 \times 6 = 630^\circ$ |