In ΔABC, D is a point on BC. If $\frac{AB}{AC}=\frac{BD}{DC}$, ∠B = 75° and ∠C = 45°, then ∠BAD is equal to:

50° 30° 60° 45°

30°

We know that, Sum of all angles of a triangle = 180o. We have, ∠B = 75° and ∠C = 45° $\frac{AB}{AC}=\frac{BD}{DC}$  AD is bisect angle A = A + B + C = 180  = ∠A = 180 - (70 + 50) = ∠BAD = \(\frac{60}{2}\) = 30o