The planes $2 x-y+4 z=5$ and $5 x-\frac{5}{2} y+10 z=6$ are |
perpendicular intersecting at an angle $\frac{\pi}{4}$ parallel passing through $\left(0,0, \frac{5}{2}\right)$ |
parallel |
The correct answer is Option (3) → parallel $P_1:2 x-y+4 z=5$ $P_2:5 x-\frac{5}{2} y+10 z=6$ here $\frac{2}{5}=\frac{-1}{-\frac{5}{2}}=\frac{4}{10}⇒P_1||P_2$ |