The planes $2 x-y+4 z=5$ and $5 x-\frac{5}{2} y+10 z=6$ are
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → parallel
$P_1:2 x-y+4 z=5$
$P_2:5 x-\frac{5}{2} y+10 z=6$
here $\frac{2}{5}=\frac{-1}{-\frac{5}{2}}=\frac{4}{10}⇒P_1||P_2$