A circular metal plate expands under heating so that its radius increases by 2%. The approximate increase in the area of the plate if the radius of the plate before heating is 10 cm, is
Answer & explanation
Correct answer: option 4
Let at any time, $x$ be the radius and $y$ be the area of the plate. Then, $y=\pi x^2$.
Let $\Delta x$ be the change in the radius and let $\Delta y$ be the corresponding change in the area of the plate. Then,
$\frac{\Delta x}{x} \times 100=2$ [Given]
When x = 10,
$\frac{\Delta x}{x} \times 100=2 \Rightarrow \frac{\Delta x}{10} \times 100=2 \Rightarrow \Delta x=\frac{2}{10}$
$\Rightarrow d x=\frac{2}{10}$ $[∵ d x \cong \Delta x]$ ....(i)
Now, $y=\pi x^2 \Rightarrow \frac{d y}{d x}=2 \pi x \Rightarrow\left(\frac{d y}{d x}\right)_{x=10}=20 \pi$
∴ $d y =\frac{d y}{d x} d x$
$\Rightarrow d y =20 \pi \times \frac{2}{10}=4 \pi \Rightarrow \Delta y=4 \pi $ $[∵ d y \cong \Delta y]$
Hence, the approximate change in the area of the plate is $4 \pi$