The area enclosed by the ellipse \(4x^2+

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Application of Integrals

Question:

The area enclosed by the ellipse $4x^2+9y^2=1$ is

Options:

$\frac{\pi}{2}$

$\frac{\pi}{3}$

$\frac{\pi}{6}$

$\pi$

Correct Answer:

$\frac{\pi}{6}$

Explanation:

Area of ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ is $\pi ab$