The area enclosed by the ellipse \(4x^2+9y^2=1\) is1\(\frac{\pi}{2}\)2\(\frac{\pi}{3}\)3\(\frac{\pi}{6}\)4\(\pi\)Answer & explanation+Correct answer: option 3Area of ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) is \(\pi ab\)
