Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Application of Integrals

Question:
The area enclosed by the ellipse \(4x^2+9y^2=1\) is
Options:
\(\frac{\pi}{2}\)
\(\frac{\pi}{3}\)
\(\frac{\pi}{6}\)
\(\pi\)
Correct Answer:
\(\frac{\pi}{6}\)
Explanation:
Area of ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) is \(\pi ab\)