Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

$ \text{Potential due to sphere of radius R_1 is }V_1 = \frac{KQ_1}{R_1}$

$ \text{Potential due to sphere of radius R_2 is }V_2 = \frac{KQ_2}{r}$

$\Rightarrow V = V_1 + V_2 = \frac{KQ_1}{R_1} + \frac{KQ_2}{r}$