A solution of solute X in benzene boils at 0.126 oC higher than benzene. What is the molality of the solution? (Kb for benzene = 2.52 K/m)
Answer & explanation
Correct answer: option 1
Elevation in boiling point, ΔTb = Kb x m
m = \(\frac{ΔTb}{Kb}\)
m = \(\frac{0.126}{2.52}\) = 0.05 m