A is 40% more than B and is 60% less than C. If C is 60% more than D, then which of the following is true?
Answer & explanation
Correct answer: option 1
Let , D = 100x
C = 100x × \(\frac{160}{100}\) = 160x
B = 160x × \(\frac{40}{100}\) = 64x
A = 64x × \(\frac{140}{100}\) = 89.6x
A is less than D by = \(\frac{100x - 89.6x}{100x}\) × 100 = 10.4%