Practicing Success
A person has to cover a distance of 90 km. If he increases his speed by 6 km/hr he reaches 4 hour early. Find his initial speed (in km/hr). |
15 6 7 9 |
9 |
Let the initial speed = x km/hr ATQ, \(\frac{90}{x}-\frac{90}{x+6}=4\) let x = 9 (by using option) \(\frac{90}{9}-\frac{90 }{15}=4\) 10 – 6 = 4 (satisfied) so, x = 9 |