A person has to cover a distance of 90 km. If he increases his speed by 6 km/hr he reaches 4 hour early. Find his initial speed (in km/hr).
Answer & explanation
Correct answer: option 4
Let the initial speed = x km/hr
ATQ,
\(\frac{90}{x}-\frac{90}{x+6}=4\)
let x = 9 (by using option)
\(\frac{90}{9}-\frac{90 }{15}=4\)
10 – 6 = 4 (satisfied)
so, x = 9