A metallic cylindrical rod is melted and recasted as a rod which has one-fourth of the radius of the original rod. Its length will be
Answer & explanation
Correct answer: option 1
Let the radius of the rod = r
We know that the volume of the rod = πr2h
and the radius of the new rod = r/4
So the volume of the new rod = π(r/4)2H
πr2h : π(r/4)2h
π(r)2h : πr2/16H
here, h/H = 1/16
So, its length will be 16 times.