What is the HCF of $\frac{4}{5}, \frac{6}{8}, \frac{8}{25}?$
Answer & explanation
Correct answer: option 2
⇒ HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)
The given fractions are: $\frac{4}{5}, \frac{6}{8}, \frac{8}{25} $.
LCM of 5, 8, 25 = 200
HCF of 4, 6, 8 = 2
The HCF of $\frac{4}{5}, \frac{6}{8}, \frac{8}{25} $ is = \(\frac{2}{200}\) = \(\frac{1}{100}\)