What is the HCF of $\frac{4}{5}, \frac{6}{8}, \frac{8}{25}?$

$\frac{1}{100}$

⇒ HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)

The given fractions are:   $\frac{4}{5}, \frac{6}{8}, \frac{8}{25} $.

LCM of 5, 8, 25 = 200

HCF of 4, 6, 8 = 2

The HCF of  $\frac{4}{5}, \frac{6}{8}, \frac{8}{25} $ is = \(\frac{2}{200}\) = \(\frac{1}{100}\)