Practicing Success
Practicing Success
CUET Preparation Today
The derivative of $\frac{tan^{-1}x}{1+tan^{-1}x}$ with respect to $tan^{-1}x$ is : |
$\frac{tan^{-1}x}{(1+tan^{-1}x)^2}$ $\frac{1}{(1+tan^{-1}x)^2}$ $(1+tan^{-1}x)^2$ $\frac{tan^{-1}x}{(1-tan^{-1}x)^2}$ |
$\frac{1}{(1+tan^{-1}x)^2}$ |
