Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

Electric Potential $V = 2 \frac{Q}{4\pi\epsilon_0 L} = \frac{2\times 4\times 10^{-6}\times 9\times 10^9}{0.2} = 36\times 10^4$