Three of the following four letter–number pairs are alike in a certain way and one is different. Choose the odd one out.
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → T – 6
Find each letter's place counted from Z (Z = 1, Y = 2, …, A = 26). This place is 27 minus the letter's place from A.
Option (1) T – 6 — T is 20th from A, so from Z it is \( 27 - 20 = 7 \); the pair shows 6, not 7.
Option (2) X – 3 — X is 24th from A, so from Z it is \( 27 - 24 = 3 \): matches.
Option (3) D – 23 — D is 4th from A, so from Z it is \( 27 - 4 = 23 \): matches.
Option (4) J – 17 — J is 10th from A, so from Z it is \( 27 - 10 = 17 \): matches.
In three pairs the number is the letter's place counted from Z; T – 6 does not follow this, so it is the odd one out.