Practicing Success
A man takes total T hours to covers a certain distance at the speed of x km/hr and comes back at y km/hr. Find the distance. |
\(\frac{xy}{x+y}\)× T \(\frac{x}{x+y}\)× T \(\frac{y}{x+y}\)× T \(\frac{xy}{x-y}\)× T |
\(\frac{xy}{x+y}\)× T |
Let the distance = d ATQ, ⇒ \(\frac{d}{x}\) + \(\frac{d}{y}\) = T ⇒ d[\(\frac{x\;+\;y}{xy}\)] = T ⇒ d = \(\frac{xy}{x+y}\) × T |