Practicing Success
If $I=\int_{-3}^{2}(|x+1|+|x+2|+|x-1|)dx$, then I equals: |
$\frac{47}{2}$ $\frac{45}{2}$ $\frac{37}{2}$ $\frac{39}{2}$ |
$\frac{47}{2}$ |
x = -2, -1, 1 critical point
$A_1+A_2+A_3+A_4=1(\frac{7+4}{2})+1(\frac{4+3}{2})+2(\frac{3+5}{2})+1(\frac{5+8}{2})=\frac{11+7+16+13}{2}=\frac{47}{2}$ |