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What is the value of cos45° sin15° ? |
$\frac{(\sqrt{3}-1)}{2} $ $\frac{(\sqrt{3}-1)}{4} $ $(\sqrt{3}+1) $ $2 \sqrt{3}-1$ |
$\frac{(\sqrt{3}-1)}{4} $ |
2cosAsinB = sin(A+B) - sin(A-B) Thus, cos45° sin15° = $\frac{1}{2}(sin(45+15) - sin(45-15))$ = $\frac{1}{2}$sin60° - sin30° = $\frac{1}{2}\frac{\sqrt{3}}{2} - \frac{1}{2}$ = $\frac{\sqrt{3}-1}{4}$ |
