Practicing Success
If A = \(\begin{bmatrix}\alpha &\beta \\-\beta &\alpha \end{bmatrix}\) and \(A+ { A }^{ T } \) = \(\begin{bmatrix}0&1\\1&0\end{bmatrix}\), then the value of \(\alpha and \beta \) is |
\(\beta = \frac{1}{2}\) and \(\alpha = 0\) \(\beta = \frac{-1}{2}\) and \(\alpha = 0\) Cannot determine values of \(\alpha \) None of the above |
Cannot determine values of \(\alpha \) |
A = \(\begin{bmatrix}\alpha &\beta \\-\beta &\alpha \end{bmatrix}\) \( { A }^{ T } \) = \(\begin{bmatrix}\alpha &-\beta \\\beta &\alpha \end{bmatrix}\) \(A+ { A }^{ T } \) = \(\begin{bmatrix}\alpha &\beta \\-\beta &\alpha \end{bmatrix}\) + \(\begin{bmatrix}\alpha &-\beta \\\beta &\alpha \end{bmatrix}\) = \(\begin{bmatrix}0&1\\1&0\end{bmatrix}\) \(A+ { A }^{ T } \) = \(\begin{bmatrix}0 &2\beta\\-2\beta &0 \end{bmatrix}\) = \(\begin{bmatrix}0&1\\1&0\end{bmatrix}\) Equating all the corresponding terms of both the matrices we get 2\(\beta \) = 1 and so \(\beta \) = \(\frac{1}{2}\) and also \(\alpha - \alpha = 0\) and so we cannot determine the values of the first variable.
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