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An object is placed at 5 cm distance in front of concave mirror of radius of curvature 15 cm. What is position of the image? |
10 cm 15 cm 20 cm 25 cm |
15 cm |
Use : \(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\) u = -5 cm , f = -7.5 cm $\Rightarrow \frac{1}{v} = \frac{-1}{7.5} +\frac{1}{5} = \frac{1}{15}$ $\Rightarrow v = 15cm$ |
