An object is placed at 5 cm distance in front of concave mirror of radius of curvature 15 cm. What is position of the image?
Answer & explanation
Correct answer: option 2
Use :
\(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\)
u = -5 cm , f = -7.5 cm
$\Rightarrow \frac{1}{v} = \frac{-1}{7.5} +\frac{1}{5} = \frac{1}{15}$
$\Rightarrow v = 15cm$