The value of $sec^2(tan^{-1}2)+cosec^2(cot^{-1}3)$ is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 15
$\sec^2(\tan^{-1}2)+cosec^2(\cot^{-1}3)$
$=1+\tan^2(\tan^{-1}2)+1+\cot^2(\cot^{-1}3)$
$=2+2^2+3^2=2+4+9$
$=15$