In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is
Answer & explanation
Correct answer: option 1
In Lyman series $\lambda_{\max }=\frac{4}{3 R}$
In Balmer series $\lambda_{\max }=\frac{36}{5 R}$. So required ratio = $\frac{5}{27}$