Practicing Success
If sin θ + cos θ = \(\sqrt {7 }\)cos θ, then value of cot θ is? |
\(\frac{6}{√7 + 1}\) \(\frac{√7 + 1}{6}\) 1 0 |
\(\frac{√7 + 1}{6}\) |
sin θ + cos θ = \(\sqrt {7 }\)cos θ divide by cos θ ⇒ tan θ + 1 = \(\sqrt {7 }\) ⇒ tan θ = \(\sqrt {7 }\) - 1 ⇒ cot θ = \(\frac{1}{\sqrt {7 } - 1}\) = \(\frac{1}{\sqrt {7 } - 1}\) × \(\frac{\sqrt {7 } + 1}{\sqrt {7 } + 1}\) = \(\frac{√7 + 1}{6}\) |